Solved practical slips for Physics

 Here are some solved practical slips for Physics:

*Slip 1: Motion in One Dimension*

A particle moves along a straight line with an initial velocity of 5 m/s. It accelerates uniformly at a rate of 2 m/s² for 3 seconds. Find its final velocity and displacement.

*Solution:*

Given:

- Initial velocity (u) = 5 m/s

- Acceleration (a) = 2 m/s²

- Time (t) = 3 seconds

Final velocity (v) = u + at

= 5 + (2 × 3)

= 11 m/s

Displacement (s) = ut + (1/2)at²

= (5 × 3) + (1/2) × 2 × 3²

= 15 + 9

= 24 meters

*Slip 2: Motion in Two Dimensions*

A projectile is launched with an initial velocity of 20 m/s at an angle of 60° above the horizontal. Find its maximum height, range, and time of flight.

*Solution:*

Given:

- Initial velocity (u) = 20 m/s

- Angle of projection (θ) = 60°

Vertical component of initial velocity (u_y) = u sin θ

= 20 sin 60°

= 17.32 m/s

Horizontal component of initial velocity (u_x) = u cos θ

= 20 cos 60°

= 10 m/s

Maximum height (h) = (u_y)² / 2g

= (17.32)² / (2 × 9.8)

= 15.53 meters

Range (R) = (u_x) × (2u_y) / g

= (10) × (2 × 17.32) / 9.8

= 35.33 meters

Time of flight (T) = 2u_y / g

= 2 × 17.32 / 9.8

= 3.53 seconds

*Slip 3: Work, Energy, and Power*

A force of 50 N acts on an object, causing it to move 10 meters in the direction of the force. If the object starts from rest and has a mass of 20 kg, find its final velocity and the work done on the object.

*Solution:*

Given:

- Force (F) = 50 N

- Displacement (s) = 10 meters

- Mass (m) = 20 kg

Work done (W) = F × s

= 50 × 10

= 500 Joules

Kinetic energy (KE) = W

= 500 Joules

Final velocity (v) = √(2KE/m)

= √(2 × 500 / 20)

= 10 m/s

*Slip 4: Rotational Motion*

A wheel with a radius of 0.5 meters rotates with an angular velocity of 2 rad/s. Find its linear velocity and centripetal acceleration.

*Solution:*

Given:

- Radius (r) = 0.5 meters

- Angular velocity (ω) = 2 rad/s

Linear velocity (v) = r × ω

= 0.5 × 2

= 1 m/s

Centripetal acceleration (a_c) = v² / r

= (1)² / 0.5

= 2 m/s²

These are just a few examples of solved practical slips for Physics. There are many more topics and problems that can be covered.

Here are some more topics for solved practical slips in Physics:

*Slip 5: Oscillations*

A simple pendulum has a length of 1 meter and a mass of 0.1 kg. Find its time period and frequency.

*Solution:*

Given:

- Length (L) = 1 meter

- Mass (m) = 0.1 kg

Time period (T) = 2π √(L/g)

= 2π √(1/9.8)

= 2 seconds

Frequency (f) = 1/T

= 1/2

= 0.5 Hz

*Slip 6: Waves*

A wave travels with a speed of 10 m/s and has a wavelength of 2 meters. Find its frequency and time period.

*Solution:*

Given:

- Speed (v) = 10 m/s

- Wavelength (λ) = 2 meters

Frequency (f) = v/λ

= 10/2

= 5 Hz

Time period (T) = 1/f

= 1/5

= 0.2 seconds

*Slip 7: Thermodynamics*

A gas expands isothermally from an initial volume of 1 liter to a final volume of 2 liters. Find the work done by the gas.

*Solution:*

Given:

- Initial volume (V1) = 1 liter

- Final volume (V2) = 2 liters

Work done (W) = nRT ln(V2/V1)

= (1 mol) × (8.314 J/mol-K) × (300 K) × ln(2/1)

= 1730 J

*Slip 8: Electromagnetism*

A current-carrying wire has a length of 2 meters and carries a current of 5 A. Find the magnetic field produced by the wire at a distance of 1 meter.

*Solution:*

Given:

- Length (L) = 2 meters

- Current (I) = 5 A

- Distance (r) = 1 meter

Magnetic field (B) = μ₀I/2πr

= (4π × 10⁻⁷ T·m/A) × (5 A) / (2π × 1 m)

= 5 × 10⁻⁷ T

*Slip 9: Optics*

A lens has a focal length of 10 cm and an object is placed at a distance of 20 cm from the lens. Find the image distance and magnification.

*Solution:*

Given:

- Focal length (f) = 10 cm

- Object distance (u) = 20 cm

Image distance (v) = f/(1 - f/u)

= 10/(1 - 10/20)

= 20 cm

Magnification (m) = v/u

= 20/20

= 1

These are just a few more examples of solved practical slips in Physics. There are many more topics and problems that can be covered.

Here are some more problems for solved practical slips in Physics:

*Slip 10: Mechanics*

A block of mass 5 kg is pulled up a frictionless incline with a force of 20 N. The incline makes an angle of 30° with the horizontal. Find the acceleration of the block.

*Solution:*

Given:

- Mass (m) = 5 kg

- Force (F) = 20 N

- Angle (θ) = 30°

Acceleration (a) = F/m sin θ

= 20/5 sin 30°

= 2 m/s²

*Slip 11: Electromagnetism*

A charge of 2 μC is placed at the origin. Find the electric field at a point 3 meters away from the charge.

*Solution:*

Given:

- Charge (q) = 2 μC

- Distance (r) = 3 meters

Electric field (E) = kq/r²

= (9 × 10⁹ N·m²/C²) × (2 × 10⁻⁶ C) / (3 m)²

= 2 × 10⁵ N/C

*Slip 12: Thermodynamics*

A system undergoes a process in which 100 J of heat is added to it. The system also does 50 J of work. Find the change in internal energy of the system.

*Solution:*

Given:

- Heat added (Q) = 100 J

- Work done (W) = 50 J

Change in internal energy (ΔU) = Q - W

= 100 - 50

= 50 J

*Slip 13: Waves*

A wave has a frequency of 50 Hz and a wavelength of 10 meters. Find the speed of the wave.

*Solution:*

Given:

- Frequency (f) = 50 Hz

- Wavelength (λ) = 10 meters

Speed (v) = λf

= 10 × 50

= 500 m/s

*Slip 14: Optics*

A lens has a focal length of 20 cm. An object is placed at a distance of 30 cm from the lens. Find the image distance and magnification.

*Solution:*

Given:

- Focal length (f) = 20 cm

- Object distance (u) = 30 cm

Image distance (v) = f/(1 - f/u)

= 20/(1 - 20/30)

= 60 cm

Magnification (m) = v/u

= 60/30

= 2

*Slip 15: Electricity*

A resistor has a resistance of 10 Ω. A current of 2 A flows through it. Find the voltage across the resistor.

*Solution:*

Given:

- Resistance (R) = 10 Ω

- Current (I) = 2 A

Voltage (V) = IR

= 2 × 10

= 20 V

Here are some more problems for solved practical slips in Physics:

*Slip 16: Magnetism*

A current-carrying wire has a length of 5 meters and carries a current of 3 A. Find the magnetic field produced by the wire at a distance of 2 meters.

*Solution:*

Given:

- Length (L) = 5 meters

- Current (I) = 3 A

- Distance (r) = 2 meters

Magnetic field (B) = μ₀I/2πr

= (4π × 10⁻⁷ T·m/A) × (3 A) / (2π × 2 m)

= 3 × 10⁻⁷ T

*Slip 17: Thermodynamics*

A system undergoes a process in which 200 J of heat is added to it. The system also does 100 J of work. Find the change in internal energy of the system.

*Solution:*

Given:

- Heat added (Q) = 200 J

- Work done (W) = 100 J

Change in internal energy (ΔU) = Q - W

= 200 - 100

= 100 J

*Slip 18: Waves*

A wave has a frequency of 100 Hz and a wavelength of 5 meters. Find the speed of the wave.

*Solution:*

Given:

- Frequency (f) = 100 Hz

- Wavelength (λ) = 5 meters

Speed (v) = λf

= 5 × 100

= 500 m/s

*Slip 19: Optics*

A lens has a focal length of 15 cm. An object is placed at a distance of 20 cm from the lens. Find the image distance and magnification.

*Solution:*

Given:

- Focal length (f) = 15 cm

- Object distance (u) = 20 cm

Image distance (v) = f/(1 - f/u)

= 15/(1 - 15/20)

= 60 cm

Magnification (m) = v/u

= 60/20

= 3

*Slip 20: Electricity*

A resistor has a resistance of 20 Ω. A voltage of 10 V is applied across it. Find the current flowing through the resistor.

*Solution:*

Given:

- Resistance (R) = 20 Ω

- Voltage (V) = 10 V

Current (I) = V/R

= 10/20

= 0.5 A

Here are some extra problems for solved practical slips in Physics:

*Slip 21: Mechanics*

A car accelerates uniformly from rest to a speed of 20 m/s in 4 seconds. Find its acceleration and the distance traveled.

*Solution:*

Given:

- Initial velocity (u) = 0 m/s

- Final velocity (v) = 20 m/s

- Time (t) = 4 seconds

Acceleration (a) = (v - u) / t

= (20 - 0) / 4

= 5 m/s²

Distance traveled (s) = ut + (1/2)at²

= 0 × 4 + (1/2) × 5 × 4²

= 40 meters

*Slip 22: Electromagnetism*

A coil has 100 turns and a radius of 0.1 meters. A current of 2 A flows through it. Find the magnetic field produced by the coil.

*Solution:*

Given:

- Number of turns (N) = 100

- Radius (r) = 0.1 meters

- Current (I) = 2 A

Magnetic field (B) = μ₀NI/2r

= (4π × 10⁻⁷ T·m/A) × 100 × 2 / (2 × 0.1)

= 0.0126 T

*Slip 23: Thermodynamics*

A system undergoes a process in which 500 J of heat is added to it. The system also does 200 J of work. Find the change in internal energy of the system.

*Solution:*

Given:

- Heat added (Q) = 500 J

- Work done (W) = 200 J

Change in internal energy (ΔU) = Q - W

= 500 - 200

= 300 J

*Slip 24: Waves*

A wave has a frequency of 200 Hz and a wavelength of 3 meters. Find the speed of the wave.

*Solution:*

Given:

- Frequency (f) = 200 Hz

- Wavelength (λ) = 3 meters

Speed (v) = λf

= 3 × 200

= 600 m/s

*Slip 25: Optics*

A lens has a focal length of 25 cm. An object is placed at a distance of 30 cm from the lens. Find the image distance and magnification.

*Solution:*

Given:

- Focal length (f) = 25 cm

- Object distance (u) = 30 cm

Image distance (v) = f/(1 - f/u)

= 25/(1 - 25/30)

= 150 cm

Magnification (m) = v/u

= 150/30

= 5