Write a ‘C’ program to accept customer details such as: Account_no, Name, Balance in account, Assume Maximum 20 customers in the bank.
Write a function to print the account no and name of each customer with
balance below Rs.100.
Solution:-
#include<stdio.h>
#include<conio.h>
struct customer
{
int accno;
char cname[20];
int bal;
};
void disp(struct customer * , int);
void main()
{
struct customer c[20];
int i,n;
clrscr();
printf("\nHOW MANY CUSTOMER U WANT");
scanf("%d",&n);
printf("\nENTER THE ACCNO,CNAME,BAL");
for(i=0;i<n;i++)
{
scanf("%d%s%d",&c[i].accno,&c[i].cname,&c[i].bal);
}
disp(&c[0],n);
getch();
}
void disp(struct customer *d,int n)
{
int i;
for(i=0;i<n;i++)
{
if(d[i].bal<100)
{
printf("\n%d\t%s",d[i].accno,d[i].cname);
}
}
}
Write a function to print the account no and name of each customer with
balance below Rs.100.
Solution:-
#include<stdio.h>
#include<conio.h>
struct customer
{
int accno;
char cname[20];
int bal;
};
void disp(struct customer * , int);
void main()
{
struct customer c[20];
int i,n;
clrscr();
printf("\nHOW MANY CUSTOMER U WANT");
scanf("%d",&n);
printf("\nENTER THE ACCNO,CNAME,BAL");
for(i=0;i<n;i++)
{
scanf("%d%s%d",&c[i].accno,&c[i].cname,&c[i].bal);
}
disp(&c[0],n);
getch();
}
void disp(struct customer *d,int n)
{
int i;
for(i=0;i<n;i++)
{
if(d[i].bal<100)
{
printf("\n%d\t%s",d[i].accno,d[i].cname);
}
}
}