Write a C++menu driven program to show class hierarchy.

Consider the following class hierarchy.
    Create a base class Employee(empcode, empname). Derive the classes Manager(designation, clubdues), Scientist(deptname, publications) and Labourer from
Employee class. Write a C++ menu driven program
1.    to accept  the details of ‘n’ employees
2.    to display the information
3.    to display all the scientist from “Chemistry Department”.


#include<conio.h>
#include<iostream.h>
#include<string.h>
#include<stdlib.h>
char ans[20];
int ch,n,a=0,b=0,i,cnt;
class employee
{
protected:int empcode;
       char empname[20];
};
class manager:protected employee
{
protected:char desg[20];
      int dues;
public:void accept1();
       void display1();
}m[10];
void manager::accept1()
{
cout<<"\n enter employee code:-";
cin>>empcode;
cout<<"\n enter employee name:-";
cin>>empname;
cout<<"\n enter designation:-";
cin>>desg;
cout<<"\n enter club-dues:-";
cin>>dues;
}
void manager::display1()
{
cout<<empcode<<"\t"
<<empname<<"\t"
<<desg<<"\t"
<<dues<<"\n";
}
class scientist:protected employee
{
protected:char dept[20],pub[20];
public:void accept2();
       void display2();
       void search(char name[20]);
}s[10];
void scientist::accept2()
{
cout<<"\n enter employee code:-";
cin>>empcode;
cout<<"\n enter employee name:-";
cin>>empname;
cout<<"\n enter department name:-";
cin>>dept;
cout<<"\n enter the publication:-";
cin>>pub;
}
void scientist::display2()
{
cout<<empcode<<"\t"
<<empname<<"\t"
<<dept<<"\t"
<<pub<<"\n";
}
void scientist::search(char name[20])
{
int i,cnt;
for(i=0;i<b;i++)
      {
       cnt=strcmp(name,ans);
       if(cnt==0)
       cout<<"\n scientist is chemistry department is:-"<<s[i].empname;
       }
}
int main()
{
int temp;
clrscr();
while(1)
{
cout<<"\n 1:accept the details";
cout<<"\n 2:display the information";
cout<<"\n 3:to display all the scientist of chemistry department";
cout<<"\n 4:exit";
cout<<"\n enter your choice";
cin>>ch;
switch(ch)
{
case 1:cout<<"\n enter how many employee:-";
       cin>>n;
       for(i=0;i<n;i++)
       {
       cout<<"\n whose information you want to enter";
       cout<<"\n press 1:for manager";
       cout<<"\n press 2:for scientist";
       cin>>temp;
       if(temp==1)
       m[a++].accept1();
       else
       s[b++].accept2();
       }
       break;
case 2:for(i=0;i<a;i++)
       m[i].display1();
       for(i=0;i<b;i++)
       s[i].display2();
       break;
case 3:strcpy(ans,"chemistry");
       s[i].search(ans);
       break;
case 4:exit(0);
default:cout<<"\n you entered wrong choice";
       }
}
getch();
return 0;
}


===============================================
OUTPUT

enter your choice1

enter how many employee:-2

whose information you want to enter
press 1:for manager                                                            
press 2:for scientist                                                          
1                                                                              

enter employee code:-112                                                             
                                                                               
enter employee name:-XYZ                                                            
                                                                               
enter designation:-ABC                                                        
                                                                               
enter club-dues:-75                                                             
                                                                               
whose information you want to enter                                            
press 1:for manager                                                            
press 2:for scientist                                                          
2
                                                                               
enter employee code:-120.                                                            
                                                                               
enter employee name:-                                                                
enter department name:-chemistry                                                
                                                                               
enter the publication:-pqr                                                     

1:accept the details                                                           
2:display the information                                                      
3:to display all the scientist of chemistry department                         
4:exit                                                                         
enter your choice2                                                             
112     XYZ     ABC      75                                                     
120     .       chemistry        pqr                                            
                                                                               
1:accept the details                                                           
2:display the information                                                      
3:to display all the scientist of chemistry department                         
4:exit
enter your choice3

scientist is chemistry department is:-.
1:accept the details
2:display the information
3:to display all the scientist of chemistry department
4:exit
enter your choice4

Write a C++ program to create class currency using operator overloading

Write a C++ program to create class currency using operator overloading:


Create a class currency containing rupees and paisa as data members.
Write a necessary member function using operator overloading for the following.
1.currency(long int rup=0,int paisa=0)
2.currency &operator +=(currency &)to add one currency to another
3.currency & operator -=(currency &) to subtracts one currency from another accept rupees & paisa from user and display it.



#include
#include
class currency
{
int r,p;
public:currency(long int rs=0,int paisa=0)
       {
       r=rs;
       p=paisa;
       }
       currency  & operator +=(currency &);
       currency  & operator -=(currency &);
};
currency & currency :: operator +=(currency &c2)
{
int a,b;
a=r+c2.r;
b=p+c2.p;
if(b>=100)
{
b=b-100;
a=a+1;
}
cout<<"\n Addition of two currency is:-";
cout<<"\n Rupees:-"<<a;
cout<<"\n Paisa:-"<<b;
return *this;
}
currency & currency::  operator -=(currency &c2)
{
int a,b;
a=r-c2.r;
b=p-c2.p;
cout<<"\n Subtraction of two currency is:-";
cout<<"\n Rupees:-"<<a;
cout<<"\n Paisa:-"<<b;
return *this;
}
int main()
{
int rs,paisa;
clrscr();
cout<<"\n\t\t Accept two currency \n\n";
cout<<"\n Enter rupees:-";
cin>>rs;
cout<<"Enter paisa";
cin>>paisa;
currency c1(rs,paisa);
cout<<"\n Enter rupees:-";
cin>>rs;
cout<<"Enter paisa";
cin>>paisa;
currency c2(rs,paisa);
c1+=c2;
c1-=c2;
getch();
return 0;
}


===================
OUTPUT:-

        Accept two currency


Enter rupees:-12
Enter paisa34
Enter rupees:-45
Enter paisa34
Addition of two currency is:-
Rupees:-57
Paisa:-68
Subtractions of two currency is:-
rupees:--33
paisa:-0