Using power function display armstrong number

#include<iostream.h>
#include<math.h>
int main()
{
int sum,n,temp,rem;
cout<<"The Armstrong number between the range 1 to 500 are : \n"; 
for(int x=1;x<=500;x++)
{
n=x;
sum=0;
temp=n;
do
{
rem=n%10;
n=n/10;
int p;
p=pow(rem,3);
sum=sum+p;
}while(n!=0);
if(sum==temp)
cout<<x<<"\t";
}
cout<<"\t";
return 0;
}

Output:
The Armstrong number between the range 1 to 500 are : 
1      153     370     371     407
 

Program to dispaly armstrong number between 1 to 500

#include<iostream.h>
int main()
{
int sum,n,temp,rem;
cout<<"The Armstrong number between the range 1 to 500 are : \n"; 
for(int x=1;x<=500;x++)
{
n=x;
sum=0;
temp=n;
do
{
rem=n%10;
n=n/10;
sum=sum+rem*rem*rem;
}while(n!=0);
if(sum==temp)
cout<<x<<"\t";
}
cout<<"\t";
return 0;
}

Output:

 The Armstrong number between the range 1 to 500 are :
1        153         370       371        407