Tuesday, December 24, 2019

Happy Christmas

Merry ChristmasЁЯШДЁЯОДЁЯОБ❄ЁЯОЕ

Merry Christmas greetings

“Christmas season is the time of sharing. Start sharing LOVE and HOPE to your FAMILY. Eventually, the Love you have shared will also be imparted to everyone in your society. Let LOVE fill the air. Merry Christmas to you and your family!”

23 December,Happy Farmers Day!

The National Farmers Day in India is also known as Kisan Divas in Hindi.

Farmer's Day is celebrated every year on 23 December,
on the birthday of the 5th Prime Minister of India,
Choudhary Charan Singh, also a farmer's leader,
who introduced many policies to improve the lives of the Indian farmers.


It is celebrated by organizing various programs, debates, seminars, quiz competitions, discussions, workshops, exhibitions, essays writing competitions and functions.

Farmers are backbone of a country and you can’t stand straight if your backbone is broken.
The life of a farmer is very tough as he works very hard day and night in all seasons for us.
Happy Farmers Day!

Sunday, December 22, 2019

National Mathematics Day.


The Indian government declared 22 December to be National Mathematics Day. This was announced by Prime Minister Manmohan Singh on 26 February 2012 at Madras University, during the inaugural ceremony of the celebrations to mark the 125th anniversary of the birth of the Indian mathematical genius Srinivasa Ramanujan (22 Dec 1887 -26 Apr 1920). On this occasion Singh also announced that 2012 would be celebrated as the National Mathematics Year.


Srinivasa Iyengar Ramanujan was born on December 22, 1887 in the present day Tamil Nadu, India. He is one of the most recognised Indian mathematicians although he had almost no formal training in pure mathematics. He is known for mathematical analysis, number theory, infinite series, and continued fractions, including solutions to mathematical problems considered to be unsolvable.

Saturday, December 21, 2019

Write a python program to check if the number is an Armstrong number or not take input from the user

Write a python program to check if the number is an Armstrong number or not take input from the user

num = int(input("Enter a number: "))
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** 3
   temp //= 10
# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")



Output:
Enter a number: 407
407 is an Armstrong number

Thursday, December 19, 2019

Java Program to Check a Leap Year

Java Program to Check a Leap Year:

public class LeapYear {
    public static void main(String[] args) {
        int year = 1900;
        boolean leap = false;
        if(year % 4 == 0)
        {
            if( year % 100 == 0)
            {
                // year is divisible by 400, hence the year is a leap year
                if ( year % 400 == 0)
                    leap = true;
                else
                    leap = false;
            }
            else
                leap = true;
        }
        else
            leap = false;
        if(leap)
            System.out.println(year + " is a leap year.");
        else
            System.out.println(year + " is not a leap year.");
    }
}

Output:
2020 is a leap year.

Python program to Count Alphabets Digits and Special Characters in a String using for loop

# Python program to Count Alphabets Digits and Special Characters in a String using for loop

string = input("Please Enter your Own String : ")
alphabets = digits = special = 0

for i in range(len(string)):
    if(string[i].isalpha()):
        alphabets = alphabets + 1
    elif(string[i].isdigit()):
        digits = digits + 1
    else:
        special = special + 1
       
print("\nTotal Number of Alphabets in this String :  ", alphabets)
print("Total Number of Digits in this String :  ", digits)
print("Total Number of Special Characters in this String :  ", special)

Python program to make a simple calculator

#  Python program to make a simple calculator
# This function adds two numbers
def add(x, y):
   return x + y
# This function subtracts two numbers
def subtract(x, y):
   return x - y
# This function multiplies two numbers
def multiply(x, y):
   return x * y
# This function divides two numbers
def divide(x, y):
   return x / y
print("Select operation.")
print("1.Add")
print("2.Subtract")
print("3.Multiply")
print("4.Divide")
# Take input from the user
choice = input("Enter choice(1/2/3/4): ")
num1 = float(input("Enter first number: "))
num2 = float(input("Enter second number: "))
if choice == '1':
   print(num1,"+",num2,"=", add(num1,num2))
elif choice == '2':
   print(num1,"-",num2,"=", subtract(num1,num2))
elif choice == '3':
   print(num1,"*",num2,"=", multiply(num1,num2))
elif choice == '4':
   print(num1,"/",num2,"=", divide(num1,num2))
else:
   print("Invalid input")


Output

Select operation.
1.Add
2.Subtract
3.Multiply
4.Divide
Enter choice(1/2/3/4): 3
Enter first number: 15
Enter second number: 14
15.0 * 14.0 = 210.0

Write C++ program to caulate height of Binary Tree from Inorder and Levelorder Traversals

Write C++ program to caulate height of Binary Tree from Inorder and Levelorder Traversals

#include  
using namespace std;
 
/* Function to find index of value 
   in the InOrder Traversal array */
int search(int arr[], int strt, int end, int value)
{
    for (int i = strt; i <= end; i++)
        if (arr[i] == value)
            return i;
    return -1;
}
 
// Function to calculate the height of the Binary Tree
int getHeight(int in[], int level[], int start,
              int end, int& height, int n)
{
 
    // Base Case
    if (start > end)
        return 0;
 
    // Get index of current root in InOrder Traversal
    int getIndex = search(in, start, end, level[0]);
 
    if (getIndex == -1)
        return 0;
 
    // Count elements in Left Subtree
    int leftCount = getIndex - start;
 
    // Count elements in right Subtree
    int rightCount = end - getIndex;
 
    // Declare two arrays for left and
    // right subtrees
    int* newLeftLevel = new int[leftCount];
    int* newRightLevel = new int[rightCount];
 
    int lheight = 0, rheight = 0;
    int k = 0;
 
    // Extract values from level order traversal array for current left subtree
    for (int i = 0; i < n; i++) {
        for (int j = start; j < getIndex; j++) {
            if (level[i] == in[j]) {
                newLeftLevel[k] = level[i];
                k++;
                break;
            }
        }
    }
 
    k = 0;
 
    // Extract values from level order traversal array for current right subtree
    for (int i = 0; i < n; i++) {
        for (int j = getIndex + 1; j <= end; j++) {
            if (level[i] == in[j]) {
                newRightLevel[k] = level[i];
                k++;
                break;
            }
        }
    }
 
    // Recursively call to calculate height of left Subtree
    if (leftCount > 0)
        lheight = getHeight(in, newLeftLevel, start,
                            getIndex - 1, height, leftCount);
 
    // Recursively call to calculate height of right Subtree
    if (rightCount > 0)
        rheight = getHeight(in, newRightLevel,
                            getIndex + 1, end, height, rightCount);
 
    // Current height
    height = max(lheight + 1, rheight + 1);
 
    // Delete Auxiliary arrays
    delete[] newRightLevel;
    delete[] newLeftLevel;
 
    // return height
    return height;
}
 
// Driver program to test above functions
int main()
{
    int in[] = { 4, 8, 10, 12, 14, 20, 22 };
    int level[] = { 20, 8, 22, 4, 12, 10, 14 };
    int n = sizeof(in) / sizeof(in[0]);
 
    int h = 0;
 
    cout << getHeight(in, level, 0, n - 1, h, n);
 
    return 0;

Write a CPP program to find the minute at which the minute hand and hour hand coincide.

Write a CPP program to find the minute at which the minute hand and hour hand coincide.

#include
#include  
using namespace std;

void find_time(int h1)
{

  int theta = 30 * h1;
  cout << "(" << (theta * 2) << "/"
       << "11"
       << ")"
       << " minutes";
}

int main()
 {
  int h1 = 3; 
  find_time(h1); 
  return 0;
}


Output :
(180/11) minutes

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