Cpp program to create class telephone to search no name and city

Create a class telephone containing name,telephone number and city as
data members and write necessary member function for the following
-search the telephone number with given name.
-search the name with given telephone number
-search all customer in a given city.

#include<iostream.h>
#include<conio.h>
#include<string.h>
class telephone
{
public:char name[30],city[30];
       int tno;
public:void get()
       {
       cout<<"enter name:-";
       cin>>name;
       cout<<"\nenter telephone number";
       cin>>tno;
       cout<<"\nenter city name:-";
       cin>>city;
       }
       void search(int tnum)
       {
       cout<<"\ntelephone number of given customer:-"<<tnum;
       }
       void search(char n[30])
       {
       cout<<"\ncustomer name of the given number"<<n;
       }
       void search(char ct[30],int tnum)
       {
       cout<<"\n"<<ct<<"  "<<tnum;
       }
};
int main()
{
int i,tno,check;
char name[30],city[30];
telephone t[3];
clrscr();
for(i=0;i<3;i++)
t[i].get();
cout<<"\nsearch the telephone number of the given name";
cout<<"\nenter customer name:-";
cin>>name;
for(i=0;i<3;i++)
{
check=strcmp(name,t[i].name);
if(check==0)
t[i].search(t[i].tno);
}
cout<<"\n\n\nsearch the name of the given telephone number";
cout<<"\nenter telephone no.:-";
cin>>tno;
for(i=0;i<3;i++)
{
if(tno==t[i].tno)
t[i].search(t[i].name);
}
cout<<"\n\n\nsearch all customer in a given city";
cout<<"\nenter city name:-";
cin>>city;
for(i=0;i<3;i++)
{
check=strcmp(city,t[i].city);
if(check==0)
t[i].search(t[i].name,t[i].tno);
}
getch();
return 0;
}

C++ Program to find tax of person salary

Consider the following class person
class person
{
char name[20];
char addr[30];
float salary;
int property;
float tax;
public:\\method
};
calculate tax amount by checking salary and the property of the person
for salary<5000         tax rate=0
for salary>=5000||<=10000    tax rate=14% of salary
for salary>=10000        tax rate=16% of salary
in this tax amount add following amt depending on the size of area
in sqr.foot
for 100 sqr.foot        amt=0
for>1000||<5000            amt=1000
for>5000||<=10000        amt=3000


#include<conio.h>
#include<iostream.h>
class person
{
char name[20],addr[30];
float sal,tax_amt;
int prop;
public:void accept();
       void display();
};
void person::accept()
{
cout<<"\n Enter the name:-";
cin>>name;
cout<<"\n Enter address:-";
cin>>addr;
cout<<"\n Enter salary:-";
cin>>sal;
cout<<"\n Enter how much Rs. of property you have:-";
cin>>prop;
tax_amt=0;
if(sal<5000)
tax_amt=tax_amt+0;
if(sal>=5000&&sal<=10000)
tax_amt=tax_amt+(sal*0.14);
if(sal>=10000)
tax_amt=tax_amt+(sal*0.16);
if(prop==1000)
tax_amt=tax_amt+0;
if(prop>1000&&prop<5000)
tax_amt=tax_amt+1000;
if(prop>5000&&prop<=10000)
tax_amt=tax_amt+3000;
}
void person::display()
{
cout<<"\n Name:-"<<name;
cout<<"\n Address:-"<<addr;
cout<<"\n Salary:-"<<sal;
cout<<"\n Property:-"<<prop;
cout<<"\n Tax Amount:-"<<tax_amt;
}
int main()
{
person p;
clrscr();
p.accept();
p.display();
getch();
return 0;
}

=====================================================
OUTPUT :  -
Enter the name:-ABC
Enter address:-XYZ
Enter salary:-5000
Enter how much Rs. of property you have:-10000

Name:-ABC
Address:-XYZ
Salary:-5000
Property:-10000
Tax Amount:-3700

C++ program for medical shoppee

Create a class medical shoppe containing
-medicine
-qty
-price
medicine details are stored into file medical.txt. when any medicine
has to be sold it is first searched into file. if found the quantity
is decremented that much quantity to be sold.

#include<iostream.h>
#include<conio.h>
#include<fstream.h>
#include<string.h>
#include<iomanip.h>
#include<stdlib.h>
#include<stdio.h>
class medical
{
public:char med[20];
       int qty,price;
public:void accept()
       {
       cout<<"\nenter the medicine name:-";
       cin>>med;
       cout<<"\nenter qty:-";
       cin>>qty;
       cout<<"enter price";
       cin>>price;
       }
       void display()
       {
       cout<<"\nmedicine name:-"<<med;
       flushall();
       cout<<"\nquantity:-"<<qty;
       cout<<"\nprice:-"<<price;
       }
       void search(char n[20],int q)
       {
       int ans=1;
       ans=strcmp(med,n);
       if (ans==0)
       qty=qty-q;
       }

};
int main()
{
medical m[3];
int i,q,ans;
char n[20];
clrscr();
fstream f1;
f1.open("a.doc",ios::trunc|ios::in|ios::out);
cout<<"\n\t\tenter the details\n";
for(i=0;i<3;i++)
{
m[i].accept();
f1.write((char *)&m[i],sizeof(m[i]));
}
f1.seekg(0);
cout<<"\nenter the medicine name which is to be sold:-";
cin>>n;
cout<<"\nhow much quantity you want:-";
cin>>q;
for(i=0;i<3;i++)
{
f1.read((char *)&m[i],sizeof(m[i]));
m[i].search(n,q);
f1.write((char *)&m[i],sizeof(m[i]));
}
cout<<"\n\t\tdisplay of all records in a file\n";
for(i=0;i<3;i++)
{
f1.read((char *)&m[i],sizeof(m[i]));
m[i].display();
}

getch();
return 0;
}


--------------------------------------------------------------------
OUTPUT


                enter the details                                              
                                                                               
enter the medicine name:-per                                                   
                                                                               
enter qty:-34                                                                  
enter price56                                                                  
                                                                               
enter the medicine name:-12                                                    
                                                                               
enter qty:-76                                                                  
enter price45                                                                  
                                                                               
enter the medicine name:-df                                                    
                                                                               
enter qty:-34                                                                  
enter price12                                                                  
                                                                               
enter the medicine name which is to be sold:-df                                
                                                                               
how much quantity you want:-12
                                                                               
                display of all records in a file                               
                                                                               
medicine name:-per                                                             
quantity:-34                                                                   
price:-56                                                                      
medicine name:-12                                                              
quantity:-76                                                                   
price:-45                                                                      
medicine name:-df                                                              
quantity:-22
price:-12

C++ program to accept and dispaly data using class date

Create a c++ class date which contain:
-date
-month
-year
write necessary member function to accept and display a data using
<< and >> operator

#include<iostream.h>
#include<conio.h>
class date
{
int d,m,y;
public:void accept()
       {
       cout<<"\nenter date:-";
       cin>>d;
       cout<<"\nenter month:-";
       cin>>m;
       cout<<"\nenter year:-";
       cin>>y;
       }
       void display()
       {
       cout<<"\n\ndate:="<<d<<"-"<<m<<"-"<<y;
       }
};
int main()
{
date d;
clrscr();
d.accept();
d.display();
getch();
return 0;
}


-------------------------------------------------------------------------
OUTPUT


enter date:-21

enter month:-02

enter year:-2015


date:=21-02-2015

write a c++ program to read distance from user. store it in the file and display it to the user.

Create a class  distance containing feet and inches as data member.
write a c++ program to read distance from user. store it in the file
 and display it to the user.
 use operator overloading for the following
 1.<<to write distance object in inches format to a file
 2.>>to read inches from file.

#include<iostream.h>
#include<conio.h>
#include<fstream.h>
class distance
{
   int feet;
   int inches;

 public:
 friend void operator <<(fstream &,distance &);
 friend void operator >>(fstream &,distance &);

};
void operator <<(fstream &fout,distance &d)
{
cout<<"\nEnter distance : ";
cout<<"\n\nEnter feet : ";
cin>>d.feet;
cout<<"\n\nEnter inches : ";
cin>>d.inches;
int finches=(d.feet*12)+d.inches;
fout<<finches<<"\n";
}
void operator >>(fstream &fin,distance &d)
{
int finches;
fin>>finches;
d.inches=finches%12;
d.feet=finches/12;
cout<<"\nDistance is : ";
cout<<d.feet<<" feet ";
cout<<d.inches<<" inches ";
}
int main()
{
clrscr();
fstream file;
distance d;
int n;
file.open("distance.dat",ios::out);

file.seekg(0);
cout<<"\nEnter how many distance you want to store";
cin>>n;
for(int i=0;i<n;i++)
{
file<<d;
}
file.close();
file.open("distance.dat",ios::in);
file.seekg(0);
for (i=0;i<n;i++)
{
file>>d;
}
getch();
return 0;
}

--------------------------------------------------------------------------------------
Output :-
Enter how many distance you want to store1                                     
                                                                               
Enter distance :                                                               
                                                                               
Enter feet : 2                                                                 
                                                                               
                                                                               
Enter inches : 3                                                               
                                                                               
Distance is : 2 feet 3 inches 

C++ program to find percentage of student using class student

 Write a C++ program to create a class Student which contains data members as Roll_Number, Stud_Name, Percentage.  Write member functions to accept Student information.  Display all details of student along with a class obtained depending on percentage. (Use array of objects)

#include<iostream.h>
#include<conio.h>
#include<string.h>
class student
{
    int rollno;
    char name[10];
    int no_of_sub;
    int marks_of_each_sub[10];
    float per,m1;
    public:
    student()
    {}
    student(int rno,char nm[],int no_sub)
    {
        rollno=rno;
        strcpy(name,nm);
        no_of_sub=no_sub;
        if(no_of_sub>0)
        {
        for(int i=0;i<no_of_sub;i++)
        {
        cout<<"enter the marks of subject:->";
        cin>>marks_of_each_sub[i];
        m1=m1+marks_of_each_sub[i];
        per=m1/no_of_sub;
        }
        }

    }
      void show()
      {
        cout<<"\n\t"<<rollno<<"\t"<<name<<"\t"<<no_of_sub<<"\t\t"<<per<<"\t";
        for(int i=0;i<no_of_sub;i++)
        {
        cout<<marks_of_each_sub[i];
        cout<<"\n\t\t\t\t\t\t";
        }
      }

};

void main()
{
   clrscr();
   student x[10];
   int rno,i,no;
   char nm[10];
   int no_sub;
   cout<<"\n\thow many no u want?";
   cin>>no;
   for(i=0;i<no;i++)
   {
    cout<<"\nenter the rno:->";
    cin>>rno;
    cout<<"\nenter the name:->";
    cin>>nm;
    cout<<"\nenter the no of subject:->";
    cin>>no_sub;
    x[i]=student( rno,nm,no_sub);
   }
   cout<<"\n\trollno"<<"\tname"<<"\tno_of_sub"<<"\tper"<<"\tmarks_of_each_sub";
   for(i=0;i<no;i++)
   {
    x[i].show();
   }
   getch();
}

VB program to check palindrome

Private Sub Command1_Click()
a = StrReverse(Text1.Text)
If a = Text1.Text Then
MsgBox "Given string is Palindrome"
Else
MsgBox "String is Not Palindrome"
End If
End Sub



Note:-A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward or forward. Allowances may be made for adjustments to capital letters, punctuation, and word dividers. Famous examples include "A man, a plan, a canal, Panama!", "Amor, Roma", "race car", "taco cat", and "No 'x' in Nixon".

OR

A palindrome is any "word" which is the same forward and backward e.g. amma, radar, noon, 371173 etc.